Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.3 - Multiplying Polynomials - Exercise Set - Page 717: 36

Answer

$16a^2-24a+9$

Work Step by Step

$(4a-3)^2=(4a)^2-2\cdot3\cdot 4a+3^2=16a^2-24a+9$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.