Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.3 - Multiplying Polynomials - Exercise Set: 25

Answer

$4a^2-9$

Work Step by Step

$(2a+3)(2a-3)=2a\cdot 2a-3\cdot 2a+2a\cdot 3-3\cdot 3=4a^2-9$
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