Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.3 - Multiplying Polynomials - Exercise Set - Page 717: 32

Answer

$9y^3+26y^2-48y+5$

Work Step by Step

$(9y-1)(y^2+3y-5)=9y(y^2)+9y(3y)+9y(-5)-1(y^2)-1(3y)-1(-5)=9y^3+27y^2-45y-y^2-3y+5=9y^3+26y^2-48y+5$
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