Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 10 - Section 10.3 - Multiplying Polynomials - Exercise Set - Page 717: 3



Work Step by Step

$-3a(2a^{2}-3a-5)$ $=(-3a)(2a^{2})+(-3a)(-3a)+(-3a)(-5)$ $=-6a^{3}+9a+15a$
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