Answer
7
Work Step by Step
$\frac{7(16-8)}{2^3}\ \longrightarrow$parentheses and exponents are resolved first
=$\frac{7(/\!\!8)}{/\!\!8}\ \longrightarrow$cancel common factors
=7
Prealgebra (7th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321955048
ISBN 13:
978-0-32195-504-3
Chapter 1 - Review - Page 92: 96
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