Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 1 - Review - Page 92: 96



Work Step by Step

$\frac{7(16-8)}{2^3}\ \longrightarrow$parentheses and exponents are resolved first =$\frac{7(/\!\!8)}{/\!\!8}\ \longrightarrow$cancel common factors =7
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