#### Answer

15

#### Work Step by Step

$\frac{5(6^2-3)}{3^2+2}\ \longrightarrow$exponents are resolved first
=$\frac{5(36-3)}{9+2}\ \longrightarrow$resolve expressions in parentheses
=$\frac{5(33)}{9+2}\ \longrightarrow$multiply
=$\frac{165}{9+2}\ \longrightarrow$add
=$\frac{165}{11}\ \longrightarrow$reduce
=$\frac{165\div11}{11\div11}\ \longrightarrow$divide
=$\frac{15}{1}=15$