Prealgebra (7th Edition)

Published by Pearson
ISBN 10: 0321955048
ISBN 13: 978-0-32195-504-3

Chapter 1 - Review - Page 92: 77

Answer

$24R2$

Work Step by Step

$\ \ \ \ \ \ \ \ 24$ $26\bigr)\overline{626}$ $\ \ \ \ \ \ \underline{52}$ $\ \ \ \ \ \ \,106$ $\ \ \ \ \ \ \,\underline{104}$ $\ \ \ \ \ \ \ \ \ \ \ 2$ $(24\times26)+2=624+2=626\checkmark$
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