#### Answer

(x-6)(x+5)

#### Work Step by Step

$x^{2}$ - x -30 = (x- 6)(x__)
step 1. Enter x as the first term of each factor
$x^{2}$ - x -30 = (x- 6)(x__)
Step 2. To find the second term of each factor, we must find two integers whose product is 18 and whose sum is -1
List pairs of factors of the constant, -30
(1,-30)(-1,30)(-2,15),(2,-15)(-3,10)(3,-10)(5,-6)(-5,6)
step 3. The correct factorization of $x^{2}$ - x - 30is the one in which the sum of the Outside and Inside products is equal to -x.
So (-6,5) satisfy the condition
$x^{2}$ - x - 30= $x^{2}$ - 6x + 5x - 30 = (x-6)(x+5)