Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Concept and Vocabulary Check - Page 399: 15

Answer

False. The given expression becomes \[\frac{4\pm \sqrt{3}}{2}=2\pm \frac{\sqrt{3}}{2}\].

Work Step by Step

Considering \[\frac{4\pm \sqrt{3}}{2}\] Simplifying further \[\begin{align} & \frac{4\pm \sqrt{3}}{2}=\frac{4}{2}\pm \frac{\sqrt{3}}{2} \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,=2\pm \frac{\sqrt{3}}{2} \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\ne 2\pm \sqrt{3} \\ \end{align}\] Therefore, the given statement is false. The correct statement regarding the given expression is \[\frac{4\pm \sqrt{3}}{2}=2\pm \frac{\sqrt{3}}{2}\]
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