# Chapter 6 - Algebra: Equations and Inequalities - 6.5 Quadratic Equations - Concept and Vocabulary Check - Page 399: 3

(x-3)(x-6)

#### Work Step by Step

$x^{2}$ - 9x + 18 = (x- 3)(x__) step 1. Enter x as the first term of each factor $x^{2}$ - 9x + 18 = (x- 3)(x__) Step 2. To find the second term of each factor, we must find two integers whose product is 18 and whose sum is -9 List pairs of factors of the constant, 18 (1,18)(2,9)(-2,-9),(3,6)(-3,-6) step 3. The correct factorization of $x^{2}$ - 9x + 18 is the one in which the sum of the Outside and Inside products is equal to -9x. So (-3,-6) satisfy the condition $x^{2}$ - 9x + 18= $x^{2}$ - 3x - 6x+ 18 = (x-3)(x-6)

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