#### Answer

The boy’s, girl’s and wife’s share were $8000, $2000 and $4000 respectively

#### Work Step by Step

If a son has born, he receives twice as Mrs Richardo, let us represent it in algebraic expression.
Let the amount that Mrs. Richardo receives be\[X\]dollars.
Then the amount of the son is \[2X\]dollars.
And if a daughter has born then, let amount of daughter is\[Y\]dollars.
then amount of Mrs. Richardo is \[2Y\]dollars.
Now if she gives birth to twins then, the amount they receive is as follows:
The boy receives 2X dollars, Mrs. Richardo receives X dollars and the girl receives\[\frac{X}{2}\]dollars.
Now the total amount they have together,
\[2X+X+\frac{X}{2}=14,000\]
Now by solving this equation for X,
\[\begin{align}
2X+X+\frac{X}{2}=14,000 & \\
3X+\frac{X}{2}=14000 & \\
\frac{7X}{2}=14000 & \\
X=4000 & \\
\end{align}\]
By putting the value of \[X\],obtain amount of money the mother and daughter will receive.
Mrs. Richardo’s share,
\[X=4000\]
The daughter’s share,
\[\frac{X}{2}=2000\]
The son’s share,
\[2X=8000\]
The boy’s, girl’s and wife’s share were$8000, $2000 and $4000 respectively.