Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 6 - Algebra: Equations and Inequalities - 6.3 Applications of Linear Equations - Exercise Set 6.3 - Page 376: 72


The boy’s, girl’s and wife’s share were $8000, $2000 and $4000 respectively

Work Step by Step

If a son has born, he receives twice as Mrs Richardo, let us represent it in algebraic expression. Let the amount that Mrs. Richardo receives be\[X\]dollars. Then the amount of the son is \[2X\]dollars. And if a daughter has born then, let amount of daughter is\[Y\]dollars. then amount of Mrs. Richardo is \[2Y\]dollars. Now if she gives birth to twins then, the amount they receive is as follows: The boy receives 2X dollars, Mrs. Richardo receives X dollars and the girl receives\[\frac{X}{2}\]dollars. Now the total amount they have together, \[2X+X+\frac{X}{2}=14,000\] Now by solving this equation for X, \[\begin{align} 2X+X+\frac{X}{2}=14,000 & \\ 3X+\frac{X}{2}=14000 & \\ \frac{7X}{2}=14000 & \\ X=4000 & \\ \end{align}\] By putting the value of \[X\],obtain amount of money the mother and daughter will receive. Mrs. Richardo’s share, \[X=4000\] The daughter’s share, \[\frac{X}{2}=2000\] The son’s share, \[2X=8000\] The boy’s, girl’s and wife’s share were$8000, $2000 and $4000 respectively.
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