# Chapter 6 - Algebra: Equations and Inequalities - 6.1 Algebraic Expressions and Formulas - Exercise Set 6.1: 38

40 ft

#### Work Step by Step

Given h= 4+ 60t - 16$t^{2}$ To find the ball’s height 3 seconds after it was kicked Step 1: substitute the value of t=3 sec in the formula h= 4+ 60(3) - 16$(3)^{2}$ Step 2: Evaluate the exponential expressions $(3)^{2}$ = 3x3 = 9 h= 4+ 60(3) - 16(9) step 3: Multiply 60(3) = 60x3 = 180 and 16(9) = 16x9= 144 h= 4+180-144 step 4: Add and subtract from left to right h= 184-144 h= 40ft Therefore the height of ball after 3 second it was kicked is 40 ft.

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