#### Answer

40 ft

#### Work Step by Step

Given
h= 4+ 60t - 16$t^{2}$
To find the ball’s height 3 seconds after it was kicked
Step 1: substitute the value of t=3 sec in the formula
h= 4+ 60(3) - 16$(3)^{2}$
Step 2: Evaluate the exponential expressions $(3)^{2}$ = 3x3 = 9
h= 4+ 60(3) - 16(9)
step 3: Multiply 60(3) = 60x3 = 180 and 16(9) = 16x9= 144
h= 4+180-144
step 4: Add and subtract from left to right
h= 184-144
h= 40ft
Therefore the height of ball after 3 second it was kicked is 40 ft.