#### Answer

-33

#### Work Step by Step

Given -$x^{2}$ -4xy +3$y^{3}$, x=-1, y=-2
Step 1: Put the value of x=-1 and y=-2 for each x and y in the expression
=-$(-1)^{2}$ -4(-1)(-2) +3$(-2)^{3}$
Step 2: Evaluate the exponential expression$(-1)^{2}$ = (-1)(-1) = 1
$(-2)^{3}$ = (-2)(-2)(-2) = -8
=-1-4(-1)(-2)+3(-8)
Step 3: Multiply 4(-1)(-2) = 8, 3(-8) = -24
= -1-8-24
Step 4: Add and Subtract from left to right
first add -1-8
-9-24 = -33