#### Answer

60 ft

#### Work Step by Step

Given
h= 4+ 60t - 16$t^{2}$
To find the ball’s height 2 seconds after it was kicked
Step 1: substitute the value of t=2 sec in the formula
h= 4+ 60(2) - 16$(2)^{2}$
Step 2: Evaluate the exponential expressions $(2)^{2}$ = 2x2 = 4
h= 4+ 60(2) - 16(4)
step 3: Multiply 60(2) = 60x2 = 120 and 16(4) = 16x4= 64
h= 4+120-64
step 4: Add and subtract from left to right
h= 124-64
h= 60ft
Therefore the height of ball after 2 second it was kicked is 60 ft.