## Thinking Mathematically (6th Edition)

Published by Pearson

# Chapter 5 - Number Theory and the Real Number System - 5.3 The Rational Numbers - Exercise Set 5.3 - Page 285: 67

#### Answer

$-\dfrac{14}{15}$

#### Work Step by Step

Use the rule $\dfrac{a}{b} \div \dfrac{c}{d} =\dfrac{a}{b} \cdot \dfrac{d}{c}$ to obtain: $=-\dfrac{7}{8} \cdot \dfrac{16}{15}$ Cancel common factors to obtain: $\require{cancel} \\=-\dfrac{7}{\cancel{8}} \cdot \dfrac{\cancel{16}2}{15}$ Multiply the numerators together and the denominators together to obtain: $=-\dfrac{7(2)}{1(15)} \\=-\dfrac{14}{15}$

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