Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 5 - Number Theory and the Real Number System - 5.3 The Rational Numbers - Exercise Set 5.3: 64

Answer

$\dfrac{7}{2}$

Work Step by Step

Convert each mixed number to an improper fraction to obtain: $=\left(\dfrac{5(2)+4}{5}\right)\left(\dfrac{4(1)+1}{4}\right) \\=\dfrac{14}{5} \cdot \dfrac{5}{4}$ Cancel common factors to obtain: $\require{cancel} \\=\dfrac{\cancel{14}7}{\cancel{5}} \cdot \dfrac{\cancel{5}}{\cancel{4}2} \\=\dfrac{7}{1} \cdot \dfrac{1}{2}$ Multiply the numerators and multiply the denominators to obtain" $=\dfrac{7(1)}{1(2)} \\=\dfrac{7}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.