## Thinking Mathematically (6th Edition)

Published by Pearson

# Chapter 4 - Number Representation and Calculation - 4.3 Computation in Positional Systems - Exercise Set 4.3 - Page 234: 1

#### Answer

$102_{four}$

#### Work Step by Step

Rightmost column: $3+3=6_{ten}=1\times 4+2\times 1=12_{four}$ record the 2, carry the 1: $.\qquad \ \$1 $.\qquad \ \ 23_{four}$ .$\quad \ +\ 13_{four}$ $.\quad \ \ \ \_\_\_\_$ $.\qquad \ \ \ \ 2_{four}$ Next column: $1+2+1=4=1\times4+0\times1=10_{four}$ record the 10: $.\qquad \ \$1 $.\qquad \ \ 23_{four}$ .$\quad +\ \ \ \ 13_{four}$ $.\quad \_\_\_\_$ $.\qquad \ 102_{four}$ result: $102_{four}$

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