Thinking Mathematically (6th Edition)

$A\cap U = \{1, 3, 5, 7\}$
Represented using the roster method, the four sets are: $U = \{0, 1, 2, 3, 4, 5, 6, 7, 8\}$ $A = \{1, 3, 5, 7\}$ $B = \{0, 2, 4, 6, 8\}$ $C = \{2, 3, 4, 5\}$ The intersection of A and U is the set that contains all elements of A that are also elements of U. $A\cap U = \{1, 3, 5, 7\}$