Thinking Mathematically (6th Edition)

$A\cap B' = \{1, 3, 5, 7\}$
Represented using the roster method, the four sets are: $U = \{0, 1, 2, 3, 4, 5, 6, 7, 8\}$ $A = \{1, 3, 5, 7\}$ $B = \{0, 2, 4, 6, 8\}$ $C = \{2, 3, 4, 5\}$ The complement of $B$ is a set of elements in $U$ but not in $B$. $B'=\{1, 3, 5, 7\}$ The intersection of $A$ and $B'$ is the set that contains all elements of $A$ that are also elements of $B'$. $A\cap B' = \{1, 3, 5, 7\}$