Answer
$A\cap B' = \{1, 3, 5, 7\}$
Work Step by Step
Represented using the roster method, the four sets are:
$U = \{0, 1, 2, 3, 4, 5, 6, 7, 8\}$
$A = \{1, 3, 5, 7\}$
$B = \{0, 2, 4, 6, 8\}$
$C = \{2, 3, 4, 5\}$
The complement of $B$ is a set of elements in $U$ but not in $B$.
$B'=\{1, 3, 5, 7\}$
The intersection of $A$ and $B'$ is the set that contains all elements of $A$ that are also elements of $B'$.
$A\cap B' = \{1, 3, 5, 7\}$
