Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 2 - Set Theory - 2.2 Subsets - Exercise Set 2.2 - Page 68: 12


{$\frac{1}{2}$,$\frac{1}{3}$} ⊄ {2,3,5}

Work Step by Step

As no element of first set is present in the second set. Therefore, {$\frac{1}{2}$,$\frac{1}{3}$} ⊄ {2,3,5}
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