Answer
{x|x x is a dog} ⊄ {x|x x is a pure bred dog}
Work Step by Step
As dogs other then the pure bred dog which are part of first set are not present in second set.
Therefore
{x|x x is a dog} ⊄ {x|x x is a pure bred dog}
Thinking Mathematically (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0321867327
ISBN 13:
978-0-32186-732-2
Chapter 2 - Set Theory - 2.2 Subsets - Exercise Set 2.2 - Page 68: 8
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
