Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 2 - Set Theory - 2.2 Subsets - Exercise Set 2.2 - Page 68: 33


$A\subseteq B$ $A\subset B$

Work Step by Step

Written using the roster method, the sets are equal to: $A=\{6, 7, 8, 9, 10, 11\}$ $B=\{2, 3, 4, 5, 6, 7, 8, 9, 10, 11\}$ We can see that: $A\subseteq B$ is true, as every element in set $A$ is also an element in set $B$. $A\subset B$ is true, as $A\subseteq B$ and $A$ and $B$ are not equal.
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