Answer
$\frac{1}{3}$
Work Step by Step
Let A denote the event that the outcome is an odd number and B be the event that the tossed die shows 5. Clearly, we have to find P(B|A).
A= {1,3,5} and A∩B= {5}
P(A)= $\frac{3}{6}$ and P(A∩B)= $\frac{1}{6}$.
P(B|A)= $\frac{P(A∩B)}{P(A)}= \frac{\frac{1}{6}}{\frac{3}{6}}= \frac{1}{3}$
