#### Answer

1/36

#### Work Step by Step

The problem asks to find the probability that the pointer will land on yellow and then 4 and then an odd number.
The “and” rule for independent events (events that occur without having either event effect the probability of the other) can extend to three or more events.
P(A and B and C)= P(A) • P(B) • P(C)
P(A and B and C)= 2/6 • 1/6 • 3/6
P(A and B and C)= 1/36
The probability of the pointer being spun three times and landing on a yellow and then a 4 and then an odd number is 1/36.