## Thinking Mathematically (6th Edition)

Published by Pearson

# Chapter 11 - Counting Methods and Probability Theory - Chapter Summary, Review, and Test - Review Exercises - Page 758: 8

#### Answer

$800$

#### Work Step by Step

Factorial Notation $n!=n(n-1)(n-2)\cdots(3)(2)(1)$ and $0!=1$(by definition) It follows that $n!=n(n-1)!$ --- $\displaystyle \frac{800!}{799!}=\frac{800(799!)}{799!}\qquad$ ... reduce the fraction (divide with $\displaystyle \frac{799!}{799!}$) $=800$

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