Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - Chapter Summary, Review, and Test - Review Exercises - Page 758: 26

Answer

$1287$

Work Step by Step

We know that if we want to select $r$ objects out of $n$ disregarding the order, we can do this in $_nC_r=\frac{n!}{(n-r)!r!}$ ways. Hence here the number of possibilities: $_{13}P_5=\frac{13!}{(13-5)!5!}=1287$
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