Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.7 Events Involving And; Conditional Probability - Exercise Set 11.7: 48

Answer

$\frac{91}{285}$

Work Step by Step

If A, B, and C are dependent events, then P(A, B, and C) = P(A)*P(B given that A occurred)*P(C given that A and B occurred) We find the probability of not selecting apple juice if we randomly select 3 cans. E: no apple juice A: grape, orange, or mango juice. B: grape, orange, or mango juice, given that one is selected C: grape, orange, or mango juice, given that two are selected P(A) = $\frac{14}{20}$ P(B) =$\frac{13}{19}$ P(C) = $\frac{12}{18}$ P(E) = $\frac{14}{20}$ .$\frac{13}{19}$. $\frac{12}{18}$ =$\frac{91}{285}$
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