#### Answer

0.008

#### Work Step by Step

If A, and B are independent events, then
P(E) = P(A)*P(B)
a.) What are the chances that three randomly selected cigarette smokers suffer from hangovers?
A: frequent hangovers
B: frequent hangovers
C: frequent hangovers
P(A) = 0.20
P(B) =0.20
P(C)= 0.20
P(E) = P(A)*P(B)*P(C)
P(E) =0.20 x 0.20 x 0.20
=0.008