Answer
The probability that at least one of three adults selected from the tobacco dependent population suffers from anxiety is 0.4686.
Work Step by Step
P(event happening at least once) = 1 - P(event does not happen)
A: does not suffer from anxiety/panic disorder
B: does not suffer from anxiety/panic disorder
C: does not suffer from anxiety/panic disorder
P(E) = 1 - [P(A)*P(B)*P(C)]
P(A) = 0.81
P(B) =0.81
P(C)= 0.81
P(E) =1 - [ P(A)*P(B)*P(C)]
P(E) =1 - [0.81 x 0.81 x 0.81]
P(E)=1 - 0.5314 =0.4686
