Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 11 - Counting Methods and Probability Theory - 11.4 Fundamentals of Probability - Exercise Set 11.4: 7

Answer

1

Work Step by Step

P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no\ of\ outcomes}$ S={1,2,3,4,5,6}, so there are 6 total outcomes. There are 6 favorable outcomes (rolling a 1,2,3,4,5,6). P(E) = $\frac{6}{6}$ = 1
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