## Thinking Mathematically (6th Edition)

$\frac{1}{2}$
P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no\ of\ outcomes}$ S={1,2,3,4,5,6}, so there are 6 total outcomes. There are 3 favorable outcomes (rolling a 4,5,6). P(E) = $\frac{3}{6}$ = $\frac{1}{2}$