#### Answer

$\frac{1}{3}$

#### Work Step by Step

P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no\ of\ outcomes}$
S={1,2,3,4,5,6}, so there are 6 total outcomes.
There are 2 favorable outcomes (rolling a 5,6).
P(E) = $\frac{2}{6}$ = $\frac{1}{3}$

Published by
Pearson

ISBN 10:
0321867327

ISBN 13:
978-0-32186-732-2

$\frac{1}{3}$

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