Answer
The distance to which the plane has flown is\[2,879\text{ feet}\].
Work Step by Step
The distance to which the plane has flown is\[AB\]and has been showcased as\[c\].
Compute the length of \[c\]using the trigonometric function of Sine as follows:
\[\begin{align}
& \text{Sin}\theta =\tfrac{\text{Side opposite to angle}\theta }{\text{Hypotenuse}} \\
& \text{Sin}10{}^\circ =\tfrac{BC}{AB} \\
& 0.172648=\tfrac{500}{AB}
\end{align}\]
On, cross multiplying both sides. We get
\[\begin{align}
& AB=\tfrac{500\text{ feet}}{0.173648} \\
& c=2879\text{ feet}
\end{align}\]
Hence, the distance to the nearest foot, the plane has flown is\[2879\text{ feet}\].
