Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - 10.6 Right Triangle Trigonometry - Exercise Set 10.6 - Page 667: 33

Answer

The length of \[x\]is \[257\text{ units}\].

Work Step by Step

In triangle ABC, Let the side adjacent to angle \[{{40}^{{}^\circ }}\]is\[a\]. Compute the length of \[x\]using the equation as shown below: \[\begin{align} & \text{Tan}\theta =\frac{\text{Side Opposite to angle}\theta }{\text{Adjacent side to angle}\theta }=\frac{AB}{BC} \\ & \text{Tan}{{40}^{\circ }}=\tfrac{x}{a} \\ & 0.8390=\tfrac{x}{a} \end{align}\] On multiplying both sides by\[a\], we get \[x=0.8390a\] In triangle ABD, Now, let the side adjacent to angle\[{{20}^{\circ }}\] is\[a+400\]. Compute the length of \[a\]using the equation as shown below: \[\begin{align} & \text{Tan}\theta =\frac{\text{Side Opposite to angle}\theta }{\text{Adjacent side to angle}\theta }=\frac{AB}{BD} \\ & \tan {{20}^{\circ }}=\tfrac{x}{a+400} \\ & 0.3639=\tfrac{x}{a+400} \\ & 0.3639=\tfrac{0.8390a}{a+400} \end{align}\] On cross multiplying both sides, we get \[\begin{align} & 0.3639\times \left( a+400 \right)=0.8390a \\ & \left( 400\times 0.3639 \right)+0.3639a=0.8390a \\ & 145.56+0.3639a=0.8390a \\ & 0.4751a=145.56 \end{align}\] On dividing both sides by\[0.4751\], we get \[\begin{align} & a=\frac{145.56}{0.4751} \\ & =306.37 \end{align}\] Now, compute the value of \[x\]by putting the value of \[a\]in the value of \[x\] as follows: \[\begin{align} & x=0.8390\times a \\ & =0.8390\times 306.37 \\ & =257.050 \\ & =257\text{ units} \end{align}\] Hence, the length of x to the nearest whole number is\[257\text{ units}\].
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