## Thinking Mathematically (6th Edition)

Published by Pearson

# Chapter 1 - Problem Solving and Critical Thinking - 1.3 Problem Solving - Exercise Set 1.3 - Page 38: 25

$\$14,300$#### Work Step by Step An automobile was purchased for$\$23,000$. $7$ years later, it's worth $\$2700$. The difference in the prices is:$23,000-2700=20,300$dollars. Assuming the car's value depreciated steadily, it depreciated at the rate of:$20,300\div7=2900$dollars per year. This would make the car's price after 3 years:$23,000-3*2900=23,000-8700=14,300\$ dollars.

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