Answer
$=\Sigma^{k}_{m=1}(m(m+1))+((n+1)(n+2))$
Work Step by Step
Separating off the final terms
$\Sigma^{n+1}_{m=1}=\Sigma^{n}_{m=1}(m(m+1))+(n+1)(n+1+1)$
Discrete Mathematics with Applications 4th Edition
by Epp, Susanna S.
Published by
Cengage Learning
ISBN 10:
0-49539-132-8
ISBN 13:
978-0-49539-132-6
Chapter 5 - Sequences, Mathematical Induction, and Recursion - Exercise Set 5.1 - Page 243: 39
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