Work Step by Step
The lower limit of $k$ is $-1$ and the upper limit is $1$. Thus, evaluate the given summation from $k=-1$ to $k=1$ to obtain: $=[(-1)^2+3] + (0^2+3) + (1^2+3) \\=(1+3)+(0+3) + (1+3) \\=4+3+4 \\=11$
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