## Discrete Mathematics with Applications 4th Edition

The formula is $\frac{k}{k+1}$ and we are looking for the product when k=3. $\frac{1}{4}$ is the answer.
Need k = 0, 1, 2, 3. Plug all these numbers into the equation $\frac{k}{k+1}$ and multiply together. (0)($\frac{1}{2}$)($\frac{2}{3}$)($\frac{3}{4}$) = $\frac{1}{4}$