Discrete Mathematics with Applications 4th Edition

Published by Cengage Learning
ISBN 10: 0-49539-132-8
ISBN 13: 978-0-49539-132-6

Chapter 5 - Sequences, Mathematical Induction, and Recursion - Exercise Set 5.1 - Page 243: 35


The formula is $\frac{k}{k+1}$ and we are looking for the product when k=3. $\frac{1}{4}$ is the answer.

Work Step by Step

Need k = 0, 1, 2, 3. Plug all these numbers into the equation $\frac{k}{k+1}$ and multiply together. (0)($\frac{1}{2}$)($\frac{2}{3}$)($\frac{3}{4}$) = $\frac{1}{4}$
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