Answer
$d=4$, $n=2$
Work Step by Step
**Example:**
Let \( d = 4 \) (which is composite) and \( n = 2 \). Then:
\[
n^2 = 2^2 = 4.
\]
Notice that \(4\) divides \( n^2 \) (since \( 4 \mid 4 \)), but \(2\) is not divisible by \(4\).
This shows that even though \(n^2\) is divisible by \(d\), \(n\) itself need not be divisible by \(d\) when \(d\) is not prime.
