Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapters 1-4 - Decimals - Test - Page 327: 24

Answer

0.8, 0.8015, $\frac{21}{25}$, $\frac{7}{8}$

Work Step by Step

$\frac{7}{8}$, 0.8, $\frac{21}{25}$, 0.8015 = $\frac{7}{8}$, $\frac{8}{10}$, $\frac{21}{25}$, $\frac{8015}{10000}$ = $\frac{875}{1000}$, $\frac{8}{10}$, $\frac{84}{100}$, $\frac{8015}{10000}$ = 0.875, 0.8, 0.84, 0.8015 It is easier to compare decimals if they are all tenths, or all hundredths, and so on. Because 7.8015 has four decimal places (ten-thousandths), write zeros to the right of 0.875, 0.8 and 0.84 so they also have four decimal places. = 0.8750, 0.8000, 0.8400, 0.8015 Now, Least to greatest order is : 0.8000, 0.8015, 0.8400, 0.8750 So, 7.005, 7.5, 7.5005, 7.505 0.8, 0.8015, $\frac{21}{25}$, $\frac{7}{8}$
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