## Basic College Mathematics (10th Edition)

$\frac{4}{31}$
= $\frac{2}{3}\div5\frac{1}{6}$ = $\frac{2}{3}\div\frac{5\times6+1}{6}$ = $\frac{2}{3}\div\frac{31}{6}$ = $\frac{2}{3}\times\frac{6}{31}$ (division of fractions is multiplication by the reciprocal of the second fraction) = $\frac{2}{1}\times\frac{2}{31}$ = $\frac{4}{31}$