Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapters 1-4 - Decimals - Test - Page 327: 20

Answer

14

Work Step by Step

$\sqrt 36 +3(8)-4^{2}$ = $\sqrt 36 +3(8)-4^{2}$ (first solve bracket & order) = $6 +3(8)-16$ = $6 +24-16$ = $6 + 8$ = 14
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