Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapters 1-10 - Cumulative Review Exercises - Page 757: 9



Work Step by Step

We have $\frac{2}{3}(\frac{7}{8}-\frac{3}{4})$ Solving $$\frac{2}{3}(\frac{7-6}{8}) = \frac{2}{3}(\frac{1}{8})$$ $$\frac{2}{24} = \frac{1}{12}$$
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