Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapters 1-10 - Cumulative Review Exercises - Page 757: 9

Answer

$\frac{1}{12}$

Work Step by Step

We have $\frac{2}{3}(\frac{7}{8}-\frac{3}{4})$ Solving $$\frac{2}{3}(\frac{7-6}{8}) = \frac{2}{3}(\frac{1}{8})$$ $$\frac{2}{24} = \frac{1}{12}$$
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