Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10:
ISBN 13:

Chapters 1-10 - Cumulative Review Exercises - Page 757: 5

Answer

$1\frac{11}{12}$

Work Step by Step

We have $6\frac{2}{3} - 4\frac{3}{4}$ Solving $$\frac{20}{3} - \frac{19}{4}$$ $$\frac{80-57}{12} = \frac{23}{12} = 1\frac{11}{12}$$
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