Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapters 1-10 - Cumulative Review Exercises - Page 757: 4



Work Step by Step

We have $4\frac{3}{5} + 5\frac{2}{3}$ Solving $$(4+5)(\frac{3}{5}+\frac{2}{3})$$ $$9\frac{9+10}{15}$$ $$9\frac{19}{15} = 10\frac{4}{15}$$
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