Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - Mixed Review Exercises - Page 700: 23



Work Step by Step

We are given the equation $-10=\frac{a}{5}-2$. In order to solve, we can first add 2 to both sides. $-10+2=\frac{a}{5}-2+2$ $-8=\frac{a}{5}$ Multiply both sides by 5. $-8\times5=\frac{a}{5}\times5$ Therefore, $a=-40$.
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