## Basic College Mathematics (10th Edition)

$a=-40$
We are given the equation $-10=\frac{a}{5}-2$. In order to solve, we can first add 2 to both sides. $-10+2=\frac{a}{5}-2+2$ $-8=\frac{a}{5}$ Multiply both sides by 5. $-8\times5=\frac{a}{5}\times5$ Therefore, $a=-40$.