Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - Mixed Review Exercises - Page 700: 24



Work Step by Step

We are given the equation $4+8p=4p+16$. In order to solve, we can first subtract 4p from both sides. $4+8p-4p=4p-4p+16$ $4+4p=16$ Subtract 4 from both sides. $4-4+4p=16-4$ $4p=12$ Divide both sides by 4. $\frac{4p}{4}=\frac{12}{4}$ Therefore, $p=3$.
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