## Basic College Mathematics (10th Edition)

Published by Pearson

# Chapter 9 - Basic Algebra - 9.8 Using Equations to Solve Application Problems - 9.8 Exercises - Page 689: 51

#### Answer

The length of the dog pen is $12$ ft and the width of the dog pen is $6$ ft.

#### Work Step by Step

Let $x =$ the width of the dog pen $2(2x) + 2(x) = 36$ $4x + 2x = 36$ $6x = 36$ $x = \frac{36}{6}$ $x = 6$ ft Let $y =$ the length of the dog pen $y = 2x$ $y = 2(6)$ $y = 12$ ft

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