Chapter 9 - Basic Algebra - 9.8 Using Equations to Solve Application Problems - 9.8 Exercises - Page 689: 48

The longer piece of the pipe is $48$ cm long and the shorter piece of the pipe is $42$ cm long.

Let $x = $ the longer length of the pipe $(x) + (x - 6) = 90$ $2x - 6 = 90$ $2x = 96$ $x = \frac{96}{2}$ $x = 48$ cm Let $y = $ the shorter length of the pipe $y = (x- 6)$ $y = 48 - 6$ $y = 42$ cm