Basic College Mathematics (10th Edition)

Published by Pearson
ISBN 10: 0134467795
ISBN 13: 978-0-13446-779-5

Chapter 9 - Basic Algebra - 9.8 Using Equations to Solve Application Problems - 9.8 Exercises - Page 689: 49

Answer

The length of the rectangle is $19$ yd.

Work Step by Step

Let $x =$ the length $2(5) + 2(x) = 48$ $10 + 2x = 48$ $2x = 38$ $x = \frac{38}{2}$ $x = 19$ yd
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